// To detect whether a circular loop exists in a linked list
public boolean findCircularLoop() {
Node slower, faster;
slower = head;
faster = head.next; // start faster one node ahead
while (true) {
// if the faster pointer encounters a NULL element
if (faster == null || faster.next == null)
return false;
// if faster pointer ever equals slower or faster's next
// pointer is ever equal to slower then it's a circular list
else if (slower == faster || slower == faster.next)
return true;
else {
// advance the pointers
slower = slower.next;
faster = faster.next.next;
}
}
}
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Answer by Richa for How to detect a loop in a linked list?
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